Integrand size = 28, antiderivative size = 187 \[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\frac {7 \sqrt {2+3 x}}{33 (1-2 x)^{3/2} (3+5 x)^{3/2}}+\frac {26 \sqrt {2+3 x}}{121 \sqrt {1-2 x} (3+5 x)^{3/2}}-\frac {575 \sqrt {1-2 x} \sqrt {2+3 x}}{3993 (3+5 x)^{3/2}}-\frac {2960 \sqrt {1-2 x} \sqrt {2+3 x}}{43923 \sqrt {3+5 x}}+\frac {592 E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{1331 \sqrt {33}}-\frac {230 \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{1331 \sqrt {33}} \]
592/43923*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-2 30/43923*EllipticF(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)+7/ 33*(2+3*x)^(1/2)/(1-2*x)^(3/2)/(3+5*x)^(3/2)+26/121*(2+3*x)^(1/2)/(3+5*x)^ (3/2)/(1-2*x)^(1/2)-575/3993*(1-2*x)^(1/2)*(2+3*x)^(1/2)/(3+5*x)^(3/2)-296 0/43923*(1-2*x)^(1/2)*(2+3*x)^(1/2)/(3+5*x)^(1/2)
Result contains complex when optimal does not.
Time = 7.09 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.52 \[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\frac {2 \left (\frac {\sqrt {2+3 x} \left (1775+13572 x-810 x^2-29600 x^3\right )}{(1-2 x)^{3/2} (3+5 x)^{3/2}}-i \sqrt {33} \left (296 E\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right )|-\frac {2}{33}\right )-181 \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right ),-\frac {2}{33}\right )\right )\right )}{43923} \]
(2*((Sqrt[2 + 3*x]*(1775 + 13572*x - 810*x^2 - 29600*x^3))/((1 - 2*x)^(3/2 )*(3 + 5*x)^(3/2)) - I*Sqrt[33]*(296*EllipticE[I*ArcSinh[Sqrt[9 + 15*x]], -2/33] - 181*EllipticF[I*ArcSinh[Sqrt[9 + 15*x]], -2/33])))/43923
Time = 0.27 (sec) , antiderivative size = 207, normalized size of antiderivative = 1.11, number of steps used = 11, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.393, Rules used = {109, 27, 169, 27, 169, 25, 169, 27, 176, 123, 129}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(3 x+2)^{3/2}}{(1-2 x)^{5/2} (5 x+3)^{5/2}} \, dx\) |
\(\Big \downarrow \) 109 |
\(\displaystyle \frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}-\frac {1}{33} \int -\frac {3 (76 x+53)}{2 (1-2 x)^{3/2} \sqrt {3 x+2} (5 x+3)^{5/2}}dx\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{22} \int \frac {76 x+53}{(1-2 x)^{3/2} \sqrt {3 x+2} (5 x+3)^{5/2}}dx+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 169 |
\(\displaystyle \frac {1}{22} \left (\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}-\frac {2}{77} \int -\frac {7 (1170 x+817)}{2 \sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{5/2}}dx\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \int \frac {1170 x+817}{\sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{5/2}}dx+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 169 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (-\frac {2}{33} \int -\frac {1725 x+1331}{\sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{3/2}}dx-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \int \frac {1725 x+1331}{\sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{3/2}}dx-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 169 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \left (-\frac {2}{11} \int \frac {3 (2960 x+511)}{2 \sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {2960 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \left (-\frac {3}{11} \int \frac {2960 x+511}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {2960 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 176 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \left (-\frac {3}{11} \left (592 \int \frac {\sqrt {5 x+3}}{\sqrt {1-2 x} \sqrt {3 x+2}}dx-1265 \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx\right )-\frac {2960 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 123 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \left (-\frac {3}{11} \left (-1265 \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-592 \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {2960 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
\(\Big \downarrow \) 129 |
\(\displaystyle \frac {1}{22} \left (\frac {1}{11} \left (\frac {2}{33} \left (-\frac {3}{11} \left (230 \sqrt {\frac {11}{3}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )-592 \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )-\frac {2960 \sqrt {1-2 x} \sqrt {3 x+2}}{11 \sqrt {5 x+3}}\right )-\frac {1150 \sqrt {1-2 x} \sqrt {3 x+2}}{33 (5 x+3)^{3/2}}\right )+\frac {52 \sqrt {3 x+2}}{11 \sqrt {1-2 x} (5 x+3)^{3/2}}\right )+\frac {7 \sqrt {3 x+2}}{33 (1-2 x)^{3/2} (5 x+3)^{3/2}}\) |
(7*Sqrt[2 + 3*x])/(33*(1 - 2*x)^(3/2)*(3 + 5*x)^(3/2)) + ((52*Sqrt[2 + 3*x ])/(11*Sqrt[1 - 2*x]*(3 + 5*x)^(3/2)) + ((-1150*Sqrt[1 - 2*x]*Sqrt[2 + 3*x ])/(33*(3 + 5*x)^(3/2)) + (2*((-2960*Sqrt[1 - 2*x]*Sqrt[2 + 3*x])/(11*Sqrt [3 + 5*x]) - (3*(-592*Sqrt[11/3]*EllipticE[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]] , 35/33] + 230*Sqrt[11/3]*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33 ]))/11))/33)/11)/22
3.30.95.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Simp[(b*c - a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f *x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Simp[1/(b*(b*e - a*f)*(m + 1)) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])
Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_ )]), x_] :> Simp[(2/b)*Rt[-(b*e - a*f)/d, 2]*EllipticE[ArcSin[Sqrt[a + b*x] /Rt[-(b*c - a*d)/d, 2]], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] && !L tQ[-(b*c - a*d)/d, 0] && !(SimplerQ[c + d*x, a + b*x] && GtQ[-d/(b*c - a*d ), 0] && GtQ[d/(d*e - c*f), 0] && !LtQ[(b*c - a*d)/b, 0])
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x _)]), x_] :> Simp[2*(Rt[-b/d, 2]/(b*Sqrt[(b*e - a*f)/b]))*EllipticF[ArcSin[ Sqrt[a + b*x]/(Rt[-b/d, 2]*Sqrt[(b*c - a*d)/b])], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ [(b*e - a*f)/b, 0] && PosQ[-b/d] && !(SimplerQ[c + d*x, a + b*x] && GtQ[(d *e - c*f)/d, 0] && GtQ[-d/b, 0]) && !(SimplerQ[c + d*x, a + b*x] && GtQ[(( -b)*e + a*f)/f, 0] && GtQ[-f/b, 0]) && !(SimplerQ[e + f*x, a + b*x] && GtQ [((-d)*e + c*f)/f, 0] && GtQ[((-b)*e + a*f)/f, 0] && (PosQ[-f/d] || PosQ[-f /b]))
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f)) Int[(a + b*x)^(m + 1)*(c + d*x)^n *(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[ 2*m, 2*n, 2*p]
Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]* Sqrt[(e_) + (f_.)*(x_)]), x_] :> Simp[h/f Int[Sqrt[e + f*x]/(Sqrt[a + b*x ]*Sqrt[c + d*x]), x], x] + Simp[(f*g - e*h)/f Int[1/(Sqrt[a + b*x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && Sim plerQ[a + b*x, e + f*x] && SimplerQ[c + d*x, e + f*x]
Time = 4.70 (sec) , antiderivative size = 228, normalized size of antiderivative = 1.22
method | result | size |
elliptic | \(\frac {\sqrt {-\left (-1+2 x \right ) \left (3+5 x \right ) \left (2+3 x \right )}\, \left (\frac {\left (\frac {2}{1815}+\frac {37 x}{18150}\right ) \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}{\left (-\frac {3}{10}+x^{2}+\frac {1}{10} x \right )^{2}}-\frac {2 \left (-20-30 x \right ) \left (-\frac {43}{87846}+\frac {296 x}{43923}\right )}{\sqrt {\left (-\frac {3}{10}+x^{2}+\frac {1}{10} x \right ) \left (-20-30 x \right )}}-\frac {146 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{219615 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}-\frac {1184 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, \left (-\frac {7 E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{6}+\frac {F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{2}\right )}{307461 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}\right )}{\sqrt {1-2 x}\, \sqrt {2+3 x}\, \sqrt {3+5 x}}\) | \(228\) |
default | \(\frac {2 \sqrt {1-2 x}\, \left (59730 \sqrt {5}\, \sqrt {7}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x^{2} \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-103600 \sqrt {5}\, \sqrt {7}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x^{2} \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}+5973 \sqrt {5}\, \sqrt {7}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-10360 \sqrt {5}\, \sqrt {7}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-17919 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )+31080 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-3108000 x^{4}-2157050 x^{3}+1368360 x^{2}+1136415 x +124250\right )}{1537305 \left (3+5 x \right )^{\frac {3}{2}} \left (-1+2 x \right )^{2} \sqrt {2+3 x}}\) | \(311\) |
(-(-1+2*x)*(3+5*x)*(2+3*x))^(1/2)/(1-2*x)^(1/2)/(2+3*x)^(1/2)/(3+5*x)^(1/2 )*((2/1815+37/18150*x)*(-30*x^3-23*x^2+7*x+6)^(1/2)/(-3/10+x^2+1/10*x)^2-2 *(-20-30*x)*(-43/87846+296/43923*x)/((-3/10+x^2+1/10*x)*(-20-30*x))^(1/2)- 146/219615*(10+15*x)^(1/2)*(21-42*x)^(1/2)*(-15*x-9)^(1/2)/(-30*x^3-23*x^2 +7*x+6)^(1/2)*EllipticF((10+15*x)^(1/2),1/35*70^(1/2))-1184/307461*(10+15* x)^(1/2)*(21-42*x)^(1/2)*(-15*x-9)^(1/2)/(-30*x^3-23*x^2+7*x+6)^(1/2)*(-7/ 6*EllipticE((10+15*x)^(1/2),1/35*70^(1/2))+1/2*EllipticF((10+15*x)^(1/2),1 /35*70^(1/2))))
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.68 \[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=-\frac {90 \, {\left (29600 \, x^{3} + 810 \, x^{2} - 13572 \, x - 1775\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1} + 2209 \, \sqrt {-30} {\left (100 \, x^{4} + 20 \, x^{3} - 59 \, x^{2} - 6 \, x + 9\right )} {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right ) + 26640 \, \sqrt {-30} {\left (100 \, x^{4} + 20 \, x^{3} - 59 \, x^{2} - 6 \, x + 9\right )} {\rm weierstrassZeta}\left (\frac {1159}{675}, \frac {38998}{91125}, {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right )\right )}{1976535 \, {\left (100 \, x^{4} + 20 \, x^{3} - 59 \, x^{2} - 6 \, x + 9\right )}} \]
-1/1976535*(90*(29600*x^3 + 810*x^2 - 13572*x - 1775)*sqrt(5*x + 3)*sqrt(3 *x + 2)*sqrt(-2*x + 1) + 2209*sqrt(-30)*(100*x^4 + 20*x^3 - 59*x^2 - 6*x + 9)*weierstrassPInverse(1159/675, 38998/91125, x + 23/90) + 26640*sqrt(-30 )*(100*x^4 + 20*x^3 - 59*x^2 - 6*x + 9)*weierstrassZeta(1159/675, 38998/91 125, weierstrassPInverse(1159/675, 38998/91125, x + 23/90)))/(100*x^4 + 20 *x^3 - 59*x^2 - 6*x + 9)
Timed out. \[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\text {Timed out} \]
\[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\int { \frac {{\left (3 \, x + 2\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} {\left (-2 \, x + 1\right )}^{\frac {5}{2}}} \,d x } \]
\[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\int { \frac {{\left (3 \, x + 2\right )}^{\frac {3}{2}}}{{\left (5 \, x + 3\right )}^{\frac {5}{2}} {\left (-2 \, x + 1\right )}^{\frac {5}{2}}} \,d x } \]
Timed out. \[ \int \frac {(2+3 x)^{3/2}}{(1-2 x)^{5/2} (3+5 x)^{5/2}} \, dx=\int \frac {{\left (3\,x+2\right )}^{3/2}}{{\left (1-2\,x\right )}^{5/2}\,{\left (5\,x+3\right )}^{5/2}} \,d x \]